Integrand size = 26, antiderivative size = 104 \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^2}{(d+e x)^2} \, dx=\frac {6 b^2 (b d-a e)^2 x}{e^4}-\frac {(b d-a e)^4}{e^5 (d+e x)}-\frac {2 b^3 (b d-a e) (d+e x)^2}{e^5}+\frac {b^4 (d+e x)^3}{3 e^5}-\frac {4 b (b d-a e)^3 \log (d+e x)}{e^5} \]
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Time = 0.07 (sec) , antiderivative size = 104, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {27, 45} \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^2}{(d+e x)^2} \, dx=-\frac {2 b^3 (d+e x)^2 (b d-a e)}{e^5}+\frac {6 b^2 x (b d-a e)^2}{e^4}-\frac {(b d-a e)^4}{e^5 (d+e x)}-\frac {4 b (b d-a e)^3 \log (d+e x)}{e^5}+\frac {b^4 (d+e x)^3}{3 e^5} \]
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Rule 27
Rule 45
Rubi steps \begin{align*} \text {integral}& = \int \frac {(a+b x)^4}{(d+e x)^2} \, dx \\ & = \int \left (\frac {6 b^2 (b d-a e)^2}{e^4}+\frac {(-b d+a e)^4}{e^4 (d+e x)^2}-\frac {4 b (b d-a e)^3}{e^4 (d+e x)}-\frac {4 b^3 (b d-a e) (d+e x)}{e^4}+\frac {b^4 (d+e x)^2}{e^4}\right ) \, dx \\ & = \frac {6 b^2 (b d-a e)^2 x}{e^4}-\frac {(b d-a e)^4}{e^5 (d+e x)}-\frac {2 b^3 (b d-a e) (d+e x)^2}{e^5}+\frac {b^4 (d+e x)^3}{3 e^5}-\frac {4 b (b d-a e)^3 \log (d+e x)}{e^5} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 165, normalized size of antiderivative = 1.59 \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^2}{(d+e x)^2} \, dx=\frac {12 a^3 b d e^3-3 a^4 e^4+18 a^2 b^2 e^2 \left (-d^2+d e x+e^2 x^2\right )+6 a b^3 e \left (2 d^3-4 d^2 e x-3 d e^2 x^2+e^3 x^3\right )+b^4 \left (-3 d^4+9 d^3 e x+6 d^2 e^2 x^2-2 d e^3 x^3+e^4 x^4\right )-12 b (b d-a e)^3 (d+e x) \log (d+e x)}{3 e^5 (d+e x)} \]
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Time = 2.20 (sec) , antiderivative size = 175, normalized size of antiderivative = 1.68
method | result | size |
default | \(\frac {b^{2} \left (\frac {1}{3} b^{2} e^{2} x^{3}+2 x^{2} a b \,e^{2}-b^{2} d e \,x^{2}+6 a^{2} e^{2} x -8 a b d e x +3 b^{2} d^{2} x \right )}{e^{4}}-\frac {e^{4} a^{4}-4 b \,e^{3} d \,a^{3}+6 b^{2} e^{2} d^{2} a^{2}-4 a \,b^{3} d^{3} e +b^{4} d^{4}}{e^{5} \left (e x +d \right )}+\frac {4 b \left (a^{3} e^{3}-3 a^{2} b d \,e^{2}+3 a \,b^{2} d^{2} e -b^{3} d^{3}\right ) \ln \left (e x +d \right )}{e^{5}}\) | \(175\) |
norman | \(\frac {\frac {\left (e^{4} a^{4}-4 b \,e^{3} d \,a^{3}+12 b^{2} e^{2} d^{2} a^{2}-12 a \,b^{3} d^{3} e +4 b^{4} d^{4}\right ) x}{d \,e^{4}}+\frac {b^{4} x^{4}}{3 e}+\frac {2 b^{2} \left (3 a^{2} e^{2}-3 a b d e +b^{2} d^{2}\right ) x^{2}}{e^{3}}+\frac {2 b^{3} \left (3 a e -b d \right ) x^{3}}{3 e^{2}}}{e x +d}+\frac {4 b \left (a^{3} e^{3}-3 a^{2} b d \,e^{2}+3 a \,b^{2} d^{2} e -b^{3} d^{3}\right ) \ln \left (e x +d \right )}{e^{5}}\) | \(181\) |
risch | \(\frac {b^{4} x^{3}}{3 e^{2}}+\frac {2 b^{3} x^{2} a}{e^{2}}-\frac {b^{4} d \,x^{2}}{e^{3}}+\frac {6 b^{2} a^{2} x}{e^{2}}-\frac {8 b^{3} a d x}{e^{3}}+\frac {3 b^{4} d^{2} x}{e^{4}}-\frac {a^{4}}{e \left (e x +d \right )}+\frac {4 b d \,a^{3}}{e^{2} \left (e x +d \right )}-\frac {6 b^{2} d^{2} a^{2}}{e^{3} \left (e x +d \right )}+\frac {4 a \,b^{3} d^{3}}{e^{4} \left (e x +d \right )}-\frac {b^{4} d^{4}}{e^{5} \left (e x +d \right )}+\frac {4 b \ln \left (e x +d \right ) a^{3}}{e^{2}}-\frac {12 b^{2} \ln \left (e x +d \right ) a^{2} d}{e^{3}}+\frac {12 b^{3} \ln \left (e x +d \right ) a \,d^{2}}{e^{4}}-\frac {4 b^{4} \ln \left (e x +d \right ) d^{3}}{e^{5}}\) | \(230\) |
parallelrisch | \(\frac {b^{4} x^{4} e^{4}+6 x^{3} a \,b^{3} e^{4}-2 x^{3} b^{4} d \,e^{3}+12 \ln \left (e x +d \right ) x \,a^{3} b \,e^{4}-36 \ln \left (e x +d \right ) x \,a^{2} b^{2} d \,e^{3}+36 \ln \left (e x +d \right ) x a \,b^{3} d^{2} e^{2}-12 \ln \left (e x +d \right ) x \,b^{4} d^{3} e +18 x^{2} a^{2} b^{2} e^{4}-18 x^{2} a \,b^{3} d \,e^{3}+6 x^{2} b^{4} d^{2} e^{2}+12 \ln \left (e x +d \right ) a^{3} b d \,e^{3}-36 \ln \left (e x +d \right ) a^{2} b^{2} d^{2} e^{2}+36 \ln \left (e x +d \right ) a \,b^{3} d^{3} e -12 \ln \left (e x +d \right ) b^{4} d^{4}-3 e^{4} a^{4}+12 b \,e^{3} d \,a^{3}-36 b^{2} e^{2} d^{2} a^{2}+36 a \,b^{3} d^{3} e -12 b^{4} d^{4}}{3 e^{5} \left (e x +d \right )}\) | \(275\) |
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Leaf count of result is larger than twice the leaf count of optimal. 267 vs. \(2 (102) = 204\).
Time = 0.27 (sec) , antiderivative size = 267, normalized size of antiderivative = 2.57 \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^2}{(d+e x)^2} \, dx=\frac {b^{4} e^{4} x^{4} - 3 \, b^{4} d^{4} + 12 \, a b^{3} d^{3} e - 18 \, a^{2} b^{2} d^{2} e^{2} + 12 \, a^{3} b d e^{3} - 3 \, a^{4} e^{4} - 2 \, {\left (b^{4} d e^{3} - 3 \, a b^{3} e^{4}\right )} x^{3} + 6 \, {\left (b^{4} d^{2} e^{2} - 3 \, a b^{3} d e^{3} + 3 \, a^{2} b^{2} e^{4}\right )} x^{2} + 3 \, {\left (3 \, b^{4} d^{3} e - 8 \, a b^{3} d^{2} e^{2} + 6 \, a^{2} b^{2} d e^{3}\right )} x - 12 \, {\left (b^{4} d^{4} - 3 \, a b^{3} d^{3} e + 3 \, a^{2} b^{2} d^{2} e^{2} - a^{3} b d e^{3} + {\left (b^{4} d^{3} e - 3 \, a b^{3} d^{2} e^{2} + 3 \, a^{2} b^{2} d e^{3} - a^{3} b e^{4}\right )} x\right )} \log \left (e x + d\right )}{3 \, {\left (e^{6} x + d e^{5}\right )}} \]
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Time = 0.38 (sec) , antiderivative size = 155, normalized size of antiderivative = 1.49 \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^2}{(d+e x)^2} \, dx=\frac {b^{4} x^{3}}{3 e^{2}} + \frac {4 b \left (a e - b d\right )^{3} \log {\left (d + e x \right )}}{e^{5}} + x^{2} \cdot \left (\frac {2 a b^{3}}{e^{2}} - \frac {b^{4} d}{e^{3}}\right ) + x \left (\frac {6 a^{2} b^{2}}{e^{2}} - \frac {8 a b^{3} d}{e^{3}} + \frac {3 b^{4} d^{2}}{e^{4}}\right ) + \frac {- a^{4} e^{4} + 4 a^{3} b d e^{3} - 6 a^{2} b^{2} d^{2} e^{2} + 4 a b^{3} d^{3} e - b^{4} d^{4}}{d e^{5} + e^{6} x} \]
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Time = 0.19 (sec) , antiderivative size = 183, normalized size of antiderivative = 1.76 \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^2}{(d+e x)^2} \, dx=-\frac {b^{4} d^{4} - 4 \, a b^{3} d^{3} e + 6 \, a^{2} b^{2} d^{2} e^{2} - 4 \, a^{3} b d e^{3} + a^{4} e^{4}}{e^{6} x + d e^{5}} + \frac {b^{4} e^{2} x^{3} - 3 \, {\left (b^{4} d e - 2 \, a b^{3} e^{2}\right )} x^{2} + 3 \, {\left (3 \, b^{4} d^{2} - 8 \, a b^{3} d e + 6 \, a^{2} b^{2} e^{2}\right )} x}{3 \, e^{4}} - \frac {4 \, {\left (b^{4} d^{3} - 3 \, a b^{3} d^{2} e + 3 \, a^{2} b^{2} d e^{2} - a^{3} b e^{3}\right )} \log \left (e x + d\right )}{e^{5}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 245 vs. \(2 (102) = 204\).
Time = 0.27 (sec) , antiderivative size = 245, normalized size of antiderivative = 2.36 \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^2}{(d+e x)^2} \, dx=\frac {{\left (b^{4} - \frac {6 \, {\left (b^{4} d e - a b^{3} e^{2}\right )}}{{\left (e x + d\right )} e} + \frac {18 \, {\left (b^{4} d^{2} e^{2} - 2 \, a b^{3} d e^{3} + a^{2} b^{2} e^{4}\right )}}{{\left (e x + d\right )}^{2} e^{2}}\right )} {\left (e x + d\right )}^{3}}{3 \, e^{5}} + \frac {4 \, {\left (b^{4} d^{3} - 3 \, a b^{3} d^{2} e + 3 \, a^{2} b^{2} d e^{2} - a^{3} b e^{3}\right )} \log \left (\frac {{\left | e x + d \right |}}{{\left (e x + d\right )}^{2} {\left | e \right |}}\right )}{e^{5}} - \frac {\frac {b^{4} d^{4} e^{3}}{e x + d} - \frac {4 \, a b^{3} d^{3} e^{4}}{e x + d} + \frac {6 \, a^{2} b^{2} d^{2} e^{5}}{e x + d} - \frac {4 \, a^{3} b d e^{6}}{e x + d} + \frac {a^{4} e^{7}}{e x + d}}{e^{8}} \]
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Time = 9.65 (sec) , antiderivative size = 203, normalized size of antiderivative = 1.95 \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^2}{(d+e x)^2} \, dx=x^2\,\left (\frac {2\,a\,b^3}{e^2}-\frac {b^4\,d}{e^3}\right )-x\,\left (\frac {2\,d\,\left (\frac {4\,a\,b^3}{e^2}-\frac {2\,b^4\,d}{e^3}\right )}{e}-\frac {6\,a^2\,b^2}{e^2}+\frac {b^4\,d^2}{e^4}\right )+\frac {b^4\,x^3}{3\,e^2}-\frac {\ln \left (d+e\,x\right )\,\left (-4\,a^3\,b\,e^3+12\,a^2\,b^2\,d\,e^2-12\,a\,b^3\,d^2\,e+4\,b^4\,d^3\right )}{e^5}-\frac {a^4\,e^4-4\,a^3\,b\,d\,e^3+6\,a^2\,b^2\,d^2\,e^2-4\,a\,b^3\,d^3\,e+b^4\,d^4}{e\,\left (x\,e^5+d\,e^4\right )} \]
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